What about animal 2?
Certainly, it cannot compete with itself, so as we count up the competitive pairs, we might think there are seven involving animal 2.
But we must be a bit more careful. We do not want to count the pairing of animal 2 and animal 1, because we have already accounted for the competiton between animals 1 and 2.
So the animal 2 competing with animal 1 square, colored green in the chart, is not counted.
So we have six new competitive pairs: animal 2 with animal 3, animal 2 with animal 4, ..., animal 2 with animal 8.
What about animal 3?
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